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Today we analyzed the frequency response of the average filter discussed in the [[Lecture36ECE438F13|previous lecture]]. More specifically we computed its discrete-space Fourier transform and looked at [[ECE_438_Fall_2009_mboutin_plotCSFTofbasicfilters|its plot]]. Using the separability of the filter greatly facilitated the computation of its Fourier transform. We discussed different ways to determine whether a filter is separable and how to separate it. We then considered another filter (edge detector). Although that filter is not separable, we were able to write it as a sum of two separable filters. | Today we analyzed the frequency response of the average filter discussed in the [[Lecture36ECE438F13|previous lecture]]. More specifically we computed its discrete-space Fourier transform and looked at [[ECE_438_Fall_2009_mboutin_plotCSFTofbasicfilters|its plot]]. Using the separability of the filter greatly facilitated the computation of its Fourier transform. We discussed different ways to determine whether a filter is separable and how to separate it. We then considered another filter (edge detector). Although that filter is not separable, we were able to write it as a sum of two separable filters. | ||
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| + | ANNOUNCEMENT: The [[Hw10_ECE438F13sln |solution]] of [[HW10ECE438F13|HW10]] is wrong. The first student to post a correct solution will get a 1% bonus. (Post your solution below the other one.) | ||
==Relevant Rhea Material== | ==Relevant Rhea Material== | ||
*[[Student_summary_spectral_analysis_2D_signalsb|A student summary of spectral analysis of 2D signals]] | *[[Student_summary_spectral_analysis_2D_signalsb|A student summary of spectral analysis of 2D signals]] | ||
Latest revision as of 06:27, 15 November 2013
Lecture 37 Blog, ECE438 Fall 2013, Prof. Boutin
Friday November 15, 2013 (Week 13) - See Course Outline.
Jump to Lecture 1, 2, 3 ,4 ,5 ,6 ,7 ,8 ,9 ,10 ,11 ,12 ,13 ,14 ,15 ,16 ,17 ,18 ,19 ,20 ,21 ,22 ,23 ,24 ,25 ,26 ,27 ,28 ,29 ,30 ,31 ,32 ,33 ,34 ,35 ,36 ,37 ,38 ,39 ,40 ,41 ,42 ,43 ,44
Today we analyzed the frequency response of the average filter discussed in the previous lecture. More specifically we computed its discrete-space Fourier transform and looked at its plot. Using the separability of the filter greatly facilitated the computation of its Fourier transform. We discussed different ways to determine whether a filter is separable and how to separate it. We then considered another filter (edge detector). Although that filter is not separable, we were able to write it as a sum of two separable filters.
ANNOUNCEMENT: The solution of HW10 is wrong. The first student to post a correct solution will get a 1% bonus. (Post your solution below the other one.)
Relevant Rhea Material
Action items
- Work on your bonus point project.
- Begin working on the last homework.
Previous: Lecture 36 Next: Lecture 38
