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We then computed the DTFT of a sampling that signal. More specifically, we used a sampling period of 1/1000.  
 
We then computed the DTFT of a sampling that signal. More specifically, we used a sampling period of 1/1000.  
 
It was observed that this sampling yields a DT signal that also sounds like a middle C.
 
It was observed that this sampling yields a DT signal that also sounds like a middle C.
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 +
Perhaps the most confusing part of the demonstration was when we pulled out the factor 1000 in front of the Dirac deltas. The reason why we did this will become clearer once we see the general relationship between the CTFT of a signal and the DTFT of a sampling of that signal. If you are still confused about that property of the Dirac deltas, please take a look at [[Homework_3_ECE438F09|this page]]. 
  
 
Relevant links:  
 
Relevant links:  

Latest revision as of 06:17, 2 September 2013


Lecture 5 Blog, ECE438 Fall 2013, Prof. Boutin

Wednesday August 28, 2013 (Week 2) - See Course Outline.

Jump to Lecture 1, 2, 3 ,4 ,5 ,6 ,7 ,8 ,9 ,10 ,11 ,12 ,13 ,14 ,15 ,16 ,17 ,18 ,19 ,20 ,21 ,22 ,23 ,24 ,25 ,26 ,27 ,28 ,29 ,30 ,31 ,32 ,33 ,34 ,35 ,36 ,37 ,38 ,39 ,40 ,41 ,42 ,43 ,44


In todays lecture, we first computed the CTFT of signal with a pure 262 hertz frequency (i.e., a CT signal that would "sound" like a middle C). We then computed the DTFT of a sampling that signal. More specifically, we used a sampling period of 1/1000. It was observed that this sampling yields a DT signal that also sounds like a middle C.

Perhaps the most confusing part of the demonstration was when we pulled out the factor 1000 in front of the Dirac deltas. The reason why we did this will become clearer once we see the general relationship between the CTFT of a signal and the DTFT of a sampling of that signal. If you are still confused about that property of the Dirac deltas, please take a look at this page.

Relevant links:

Action items:


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