Revision as of 05:11, 3 September 2008 by Anders89 (Talk)

Find Conjugate

$ 5 - 3*i = 5 + 3*i $


$ 21 + 15*i = 21 - 15*i $


Perform Operation

$ (2 + 3*i) - (6 - 4*i) = -4 + 7*i $


$ 7*i \times (7 - 3*i) = 49*i - 21*i^2 = 49*i - 21*(-1) = 21 + 49*i $

Retrieved from "https://www.projectrhea.org/rhea/index.php?title=HW1.3_Steve_Anderson_-_Examples_with_Solutions_ECE301Fall2008mboutin&oldid=6543"
Shortcuts
Help Main Wiki Page Random Page Special Pages Log in
Search

Alumni Liaison

Correspondence Chess Grandmaster and Purdue Alumni

Prof. Dan Fleetwood