Revision as of 05:11, 3 September 2008 by Anders89 (Talk)

Find Conjugate

$ 5 - 3*i = 5 + 3*i $


$ 21 + 15*i = 21 - 15*i $


Perform Operation

$ (2 + 3*i) - (6 - 4*i) = -4 + 7*i <math> 7*i \times (7 - 3*i) = 49*i - 21*i^2 = 49*i - 21*(-1) = 21 + 49*i $

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Alumni Liaison

Ph.D. on Applied Mathematics in Aug 2007. Involved on applications of image super-resolution to electron microscopy

Francisco Blanco-Silva