Revision as of 00:49, 25 September 2008 by Rveerama (Talk)

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Since the boxes are indistinguishable and so are the balls, this would be like making stacks of 3 balls from 5 and the only difference between the stacks would be the number of balls present. then we would have: 0 0 5 0 1 4 0 3 2 3 1 1 2 2 1

ways of placing the balls...hence this would give us 5 ways of arranging teh balls.

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