Since the boxes are indistinguishable and so are theobjects, this would be like making stacks of 3 objects from 5 and the only difference between the stacks would be the number of objects present. then we would have: [0 0 5] [0 1 4] [0 3 2] [3 1 1] [2 2 1]
ways of placing the objects...hence this would give us 5 ways of arranging teh objects. --Rveerama 05:44, 25 September 2008 (UTC)
