Revision as of 15:45, 18 September 2008 by Huang122 (Talk)

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$ e^2jt = te^(-2jt) $
$ e^2jt = te^(-2jt) $

=>$ \cos(2t)=\frac{e^{2jt}+e^{-2jt}}{2} $

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Abstract algebra continues the conceptual developments of linear algebra, on an even grander scale.

Dr. Paul Garrett