Since the boxes are indistinguishable and so are the balls, this would be like making stacks of 3 balls from 5 and the only difference between the stacks would be the number of balls present. then we would have: [0 0 5] [0 1 4] [0 3 2] [3 1 1] [2 2 1]
ways of placing the balls...hence this would give us 5 ways of arranging teh balls.
