(Periodic Functions)
 
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=Course Notes for lecture 4, [[Main_Page_ECE301Fall2008mboutin|ECE301 Fall 2008, Prof. Boutin]]=
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Note: these were taken by students: they are NOT the official instructor's notes. Watch out for typos and mistakes!
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==Periodic Functions==
 
==Periodic Functions==
 
The definition of a periodic function given in class is as follows:
 
The definition of a periodic function given in class is as follows:
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As an example, we can use the function <math>x(n) = e^{\omega_0 j n}</math>.
 
As an example, we can use the function <math>x(n) = e^{\omega_0 j n}</math>.
 
To prove this, we do the following:
 
To prove this, we do the following:
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<font size="4">
 
<font size="4">
 
<math>x(n+N) = x(n)</math>
 
<math>x(n+N) = x(n)</math>
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<math>e^{\omega_0 j n} e^{2\pi j N} = e^{\omega_0 j n}</math>
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<math>e^{\omega_0 j n} e^{\omega_0 j N} = e^{\omega_0 j n}</math>
  
  
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Put yet another way:  if the equation is of the form <math>e^{\omega_0 j n}</math> and <math>\omega_0</math> is made up of <math>\pi</math> and a rational component (contains no irrationals besides <math>\pi</math>) then the function is periodic.
 
Put yet another way:  if the equation is of the form <math>e^{\omega_0 j n}</math> and <math>\omega_0</math> is made up of <math>\pi</math> and a rational component (contains no irrationals besides <math>\pi</math>) then the function is periodic.
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[[Main_Page_ECE301Fall2008mboutin|Back to ECE301 Fall 2008, Prof. Boutin]]
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[[ECE301|Back to ECE301]]

Latest revision as of 05:12, 2 February 2011

Course Notes for lecture 4, ECE301 Fall 2008, Prof. Boutin

Note: these were taken by students: they are NOT the official instructor's notes. Watch out for typos and mistakes!

Periodic Functions

The definition of a periodic function given in class is as follows: The function x(n) is periodic if and only if there exists an integer N such that x(n+N) = x(n). The value of N is called the "period".

As an example, we can use the function $ x(n) = e^{\omega_0 j n} $. To prove this, we do the following:

$ x(n+N) = x(n) $


$ e^{\omega_0 j (n+N)} = e^{\omega_0 j n} $


$ e^{\omega_0 j n} e^{\omega_0 j N} = e^{\omega_0 j n} $


$ e^{\omega_0 j N} = 1 $


$ \cos(\omega_0 N) + j\sin(\omega_0 N) = 1 $


---Which is true if:

$ \omega_0 N = k2\pi $ (where k is an integer)

---at some point.


This leads to the conclusion that if $ {\omega_0 \over 2\pi} = {k \over N} $

or, put another way, $ {\omega_0} \over {2\pi} $ is a rational number, then the function is periodic.

Put yet another way: if the equation is of the form $ e^{\omega_0 j n} $ and $ \omega_0 $ is made up of $ \pi $ and a rational component (contains no irrationals besides $ \pi $) then the function is periodic.


Back to ECE301 Fall 2008, Prof. Boutin

Back to ECE301

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Correspondence Chess Grandmaster and Purdue Alumni

Prof. Dan Fleetwood