(New page: Category:MA453Spring2009Walther If g^k=1 then dividing by g^k you get g^(-k)=1. So ord(1/g) is less than or equal to ord(g). This goes both ways, so equality must hold. --~~~~) |
|||
| Line 4: | Line 4: | ||
--[[User:Awika|Awika]] 14:42, 30 January 2009 (UTC) | --[[User:Awika|Awika]] 14:42, 30 January 2009 (UTC) | ||
| + | |||
| + | [[Question about Chapter 3, Problem 4]] | ||
Revision as of 09:00, 1 February 2009
If g^k=1 then dividing by g^k you get g^(-k)=1. So ord(1/g) is less than or equal to ord(g). This goes both ways, so equality must hold.
--Awika 14:42, 30 January 2009 (UTC)
