Contents
Energy of a CT signal
$ E = \int_{t1}^{t2} |x(t)|^2\ dt \! $
Power of a CT signal
$ P = \frac{1}{t2-t1} \int_{t2}^{t1} |f(t)|^2\ dt \! $
Energy of a DT signal
$ E = \sum_{n=n1}^{n2} |x[n]|^2 $
Power of a DT signal
This one may not be right, I took an educated guess $ P = \frac{1}{n2-n1+1} \sum_{n=n1}^{n2} |x[n]|^2 $
