Signal
The signal used was $ cos(3t) $.
Energy Equation
$ E = \int_{0}^{3 \pi}(|cos(3t)|^2 dt) $
$ E = \frac{x}{2} + \frac{1}{12} sin(6x) |_{0}^{3 \pi} $
$ sin(18 \pi)/12 $ is -3.333e^-14, so it is rounded to 0.
$ E = \frac{3 \pi}{2} $
Power Equation
$ P = \frac{1}{3 \pi - 0} \int_{0}^{3 \pi}(|cos(3t)|^2 dt) $
$ P = \frac{x}{6 \pi} + \frac{1}{36 \pi} sin(6x) |_{0}^{3 \pi} $
$ sin(18 \pi)/36 \pi $ is -1.111e^-14, so it is rounded to 0.
$ P = \frac{1}{2} $
