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QE2013_AC-3_ECE580-4

Part 1,2,3,4,5

(i)
Solution:
$ x(3) = x(2) + 2u(2) = x(1) + 2u(1) + 2u(2) = x(0) + 2u(0) + 2u(1) + 2u(2) $

$ \because x(0) = 3, x(3) = 9 $

$ \therefore \ Constraint: 2u(0) + 2u(1) + 2u(2) = 6 $

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