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Example of Computation of Fourier series of a CT SIGNAL

A practice problem on "Signals and Systems"


Signal

$ x(t) = 5cos(2t) + 3sin(4t)\! $


Fourier Series

$ x(t) = 5(\frac{e^{j2t} + e^{-j2t}}{2}) + 3(\frac{e^{j4t} - e^{-j4t}}{2j}) \! $

We take $ \omega_0 = 2\! $

$ x(t) = \frac{5}{2}e^{j2t} + \frac{5}{2}e^{-j2t} + \frac{3}{2j}e^{2j2t} - \frac{3}{2j}e^{-2j2t}\! $

Fourier Coefficients

From the Fourier Series, we determine the coefficients to be:

$ a_1 = a_{-1} = \frac{5}{2}\! $

$ a_2 = a_{-2} = \frac{3}{2j}\! $

Other Coefficients

$ w_0 = 2\! $

$ x(t) = \sum^{\infty}_{k = -\infty} a_ke^{jKw_0t}\! $

where $ a_k = \frac{1}{T}\int{0}^{T} x(t)e^{-jKw_0t}dt\! $

According to the Formula, $ a_k = 0\! $ whenever $ K \neq \pm2, \pm 4\! $


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