Homework 1 Solution, ECE302, Spring 2013, Prof. Boutin

1.6a) b),

1.7,

2.1,

2.2,

2.4,

2.12,

2.22,

2.23,

2.24,

2.28

Questions/comments/Discussion=

Please feel free to ask any questions you may have here. Also, please correct any mistakes in the solution if you find any, thanks! -TA

Note:

1. You can also try to do 2.24 by set operation, which is a more complicated but rigorous approach.

2. [1,12] is the closed interval between 1 and 12, which contains all the real number. It's not the same as {1,2,3,...,12}.