Practice Question on sampling and reconstruction (related to Nyquist rate)

The signal

$ x(t)= e^{j \pi t }\frac{\sin (3 \pi t)}{\pi t} $

is sampled with a sampling period T. For what values of T is it possible to reconstruct the signal from its sampling?

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Answer 1

x(w) = (1/2pi) F(e^jtpi)*F(sin(3tpi)/tpi)

        = (1/2pi) [2pi delta(w-pi)] * [u(w+3pi)-u(w-3pi)]

        = u(w-pi+3pi) - u(w-pi-3pi)

        = u(w+2pi) - u(w-4pi)

w_m=4pi

Nyquist Rate = 2w_m = 8pi

Since we should sample w_s > 8pi

w_s = 2pi/T > 8pi

T < 1/4 in order to be able to reconstruct the signal using Nyquist.
--Ssanthak 13:01, 21 April 2011 (UTC)

Answer 2

Write it here

Answer 3

Write it here.

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