Revision as of 07:21, 5 October 2008 by Nclaus (Talk)

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The total number of ways could be found by enumerating all the possible cases, which are

B1 B2 B3

[5 0 0]

[4 1 0]

[3 2 0]

[3 1 1]

[2 2 1]

Hence 5 is the answer.


Comments:

Hi, the only addition that I would make to your solution is to demonstrate why B1 >= B2 >= B3. Otherwise, it isn't clear why [1 4 0] is not a possible case.

--Nathan Claus 12:21, 5 October 2008 (UTC)

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