Revision as of 20:57, 24 September 2008 by Hyoong (Talk)

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By listing the possibilities, we get:

3 + 1 + 1 = 5 2 + 2 + 1 = 5

4 + 1 + 0 = 5 5 + 0 + 0 = 5 3 + 2 + 0 = 5

There are 2 ways if we want all the boxes to have an object, if not there are 2 + 3 = 5 ways.

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Ph.D. on Applied Mathematics in Aug 2007. Involved on applications of image super-resolution to electron microscopy

Francisco Blanco-Silva