Revision as of 12:51, 24 September 2008 by Tmsteinh (Talk)

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I made three colums, all labeled "Box" to signify the three indistinguishable boxes. Writing out the combinations I found there could be:

5 in one 4 in one and 1 in another 3 in one, 1 in another, and 1 in the last 3 in one and 3 in another 2 in one, 1 in another, and 2 in the last

for a total of five solutions.

--Tmsteinh 17:51, 24 September 2008 (UTC)

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