Recall: $ \omega =2\pi f $
The highest frequency of the continuous signal is $ f=\frac{\omega}{2\pi} $
According to the Sampling Theorem, sample rate $ f_s>=2f $
So the maximum T is $ \frac{4\pi}{\omega} $.
Recall: $ \omega =2\pi f $
The highest frequency of the continuous signal is $ f=\frac{\omega}{2\pi} $
According to the Sampling Theorem, sample rate $ f_s>=2f $
So the maximum T is $ \frac{4\pi}{\omega} $.