Explain InverseCTFT - Rhea
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Revision as of 20:48, 9 September 2010 by
Zhao148
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Inverse DT Fourier Transform
$ \, x(t)=\mathcal{F}^{-1}(\mathcal{X}(\omega))=\mathcal{F}^{-1}(\mathcal{X}(2\pi f))=\frac{1}{2\pi}\int_{-\infty}^{\infty}\mathcal{X}(2\pi f)e^{i2\pi ft} d2\pi f= \int_{-\infty}^{\infty}X(f)e^{i2\pi ft} df \, $
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Ph.D. on Applied Mathematics in Aug 2007. Involved on applications of image super-resolution to electron microscopy
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Francisco Blanco-Silva
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