Explain CTFT cpxexp - Rhea
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Revision as of 14:59, 9 September 2010 by
Zhao148
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CTFT of a complex exponential
$ x(t)=e^{i\omega_0 t} $
$ X(f)= \mathcal{X}(2\pi f)=2\pi \delta (2\pi f-\omega_0) $
$ Since\text{ } k\delta (kt)=\delta (t),\forall k\ne 0 $
$ X(f)=\delta (f-\frac{\omega_0}{2\pi}) $
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