Revision as of 08:45, 2 December 2009 by Snagy (Talk | contribs)


HW 12

Does anyone know how to do 2, 3, 5, 7, or 8?

  • Here's what I did for problem two. Construct along EF a length equal to BC (prop 2), then construct an angle, at E, called MEF, such that angle MEF = angle ABC (prop 23). Then construct along segment EM a length EN equal to AB. Proposition four suggests triangles NEF and ABC are congruent, and from there the argument is more or less the same.


any hints for # 1?

Back to MA460 (Fall2009Walther) Homework

Alumni Liaison

Abstract algebra continues the conceptual developments of linear algebra, on an even grander scale.

Dr. Paul Garrett