Revision as of 04:45, 20 July 2009 by Mboutin (Talk | contribs)

$ \sum_{n = M}^N \alpha^n = \alpha^M - \alpha^{N-1} / (1 - \alpha) $

  • What if $ \alpha=1 $????

Alumni Liaison

Correspondence Chess Grandmaster and Purdue Alumni

Prof. Dan Fleetwood