Revision as of 11:24, 10 December 2008 by Jmason (Talk)

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#30 p.715

What are other people getting for the solution? I got

$ \pi \sqrt{3} (e^{\pi/2}+1) $

which is hardly a nice answer, but I guess any answer is good when it comes to surface areas. --John Mason

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Ph.D. on Applied Mathematics in Aug 2007. Involved on applications of image super-resolution to electron microscopy

Francisco Blanco-Silva