The solution is very simple, and doesn't require that you use series, just some inductive logic and limits.--John Mason 16:58, 17 October 2008 (UTC)
If you had 8 teams:
- All 8 play at least 1 game.
- 4 winners of the 1st games play two games.
- 2 winners of the 2nd games play again for a third time.
- Average would be $ \frac{(8*4 + 2*2 + 2*3)}{8} $
