Revision as of 09:17, 10 July 2008 by Dvtran (Talk)

Since all the $ f_{n} $ are AC, there exists $ f_{n}^{'} $ such that $ f_{n}(x)=f_{n}(x)-f_{n}(0)=\int_{0}^{x}f_{n}^{'}(t)dt<\math> and <math>f_{n}^{'}<\math> are nonnegative almost everywhere. Let <math>g_{n}(x)= \sigma_{1}^{n}f_{n}(x)<\math>S $

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Ph.D. 2007, working on developing cool imaging technologies for digital cameras, camera phones, and video surveillance cameras.

Buyue Zhang