I think for part b.) we use Bernoilli trials, so the solution would be found by (10 choose 0)*(.6^10)*(.4^0)
Does anyone understand part C. It's confusing me. --Krwade 20:48, 24 February 2009 (UTC)
I think for part b.) we use Bernoilli trials, so the solution would be found by (10 choose 0)*(.6^10)*(.4^0)
Does anyone understand part C. It's confusing me. --Krwade 20:48, 24 February 2009 (UTC)