Revision as of 06:43, 9 November 2008 by Atlyles (Talk)

(diff) ← Older revision | Latest revision (diff) | Newer revision → (diff)

$ f_X (x;\lambda)= \lambda e^{-\lambda x} $

  • to find $ \hat \lambda_{ml} $ maximize $ \lambda e^{-\lambda x} $ by taking the derivative
  • $ -e^{-\hat \lambda x} - \hat \lambda x e^{-\hat \lambda x} = 0 $
  • $ \hat \lambda x = 1 $
  • $ \hat \lambda = 1/x $

Alumni Liaison

Basic linear algebra uncovers and clarifies very important geometry and algebra.

Dr. Paul Garrett