Revision as of 21:59, 12 November 2008 by Ricec (Talk)

I don't have a clue... ideas? help?


Since $ Z_p $ with p prime is a field, $ Z_p[x]/<f(x)> $ is a field (thm 17.5 corollary 1).

$ Z_p[x]/<f(x)> $ only has elements that are a linear combination of the n terms 1, x ,x^2, ..., x^(n-2), n^(n-1) because any elements of higher degree can be reduced down to a lower degree using the fact that f(x) = 0. Each of the n terms has p possible coefficients, yielding p^n possible elements.

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Ph.D. on Applied Mathematics in Aug 2007. Involved on applications of image super-resolution to electron microscopy

Francisco Blanco-Silva