How do you prove that an element and its inverse have the same order? I understand the idea but do not know how to prove it.
-Wooi-Chen
I thought this worked as a proof.
$ g^k=1 $ element g having order of k $ (g^k)^-1=(1)^-1 $ $ g^-k=1 $ $ (g^-1)^k=1 $ inverse of g having order of k
This could be wrong, but it makes sense.
-Daniel
