Theorem 5.7 For n>1, A_n has order n!/2.
I was wandering how do you know when to use this cause I think I got confused on the last homework.
Remember, $ A_{n} $ is the group of all permutations of a set of order n, so the order is only n!/2 if you're looking at a group isomorphic to $ A_{n} $. In that case you can use it, but in any other case, you can't.
--Dfreidin 22:11, 14 September 2008 (UTC)
