Revision as of 11:59, 20 October 2008 by Pmavery (Talk)

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The Question Asks for: P(H2|H1)

P(H2|H1) = P[H2 n H1]/P[H1]

So: P[H1] = Integral from 0 to 1 q(2q)dq

P(H2 n H1) = Integral from 0 to 1 q^2(2q)dq

Solve for both and plug into orginal equation P(H2|H1).

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Basic linear algebra uncovers and clarifies very important geometry and algebra.

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