Seung Seob Lee-am I the only one? or is it an error? ECE301Fall2008mboutin - Rhea
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Revision as of 19:42, 3 December 2008 by
Lee251
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Consider the signal
$ x[n]=a^{n}u[n] $
$ X(z)=\sum_{n=-\infty}^{\infty}a^{n}u[n]z^{-n}= $
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