Revision as of 17:40, 15 October 2008 by Cdleon (Talk)

EXAM 1

Problem 1.

is

$ x(t) = \sum_{k = -\infty}^\infty \frac{1}{(t+2k)^{2}+1} $

periodic?

We know that for a signal to be periodic

$ x(t) = x(t + T) $

So we shift the function by a arbitrary number to try to prove the statement above

$ x(t+1) = \sum_{k = -\infty}^\infty \frac{1}{(t+1+2k)^{2}+1} $


$ x(t+4) = \sum_{k = -\infty}^\infty \frac{1}{(t+2(\frac{1}{2}+k))^{2}+1} $

Then we set $ r = \frac{1}{2}+k $ to yield,

$ = \sum_{k = -\infty}^\infty \frac{1}{(t+2r)^{2}+1} $

Since this is equivalent to x(t) the signal is periodic.

Alumni Liaison

BSEE 2004, current Ph.D. student researching signal and image processing.

Landis Huffman