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Inverse Fourier Transform

$ \chi(\omega) = 2\pi \sigma(\omega - \pi) <\math> <math> x[n] = frac{1}{2\pi}\int_{-\infty}^{\infty} \sigma(\omega-\pi)e^{j\omega t} dw $

$ x[n] = \int_{-\infty}^\infty \sigma(\omega - \pi)e^{j\omega t} dw $

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Ryne Rayburn