Revision as of 07:20, 8 October 2008 by Huang122 (Talk)

Let x(t)= $ cos(t) $


Then

$ x(t)=\frac{1}{2\pi}\int_{-\infty}^{\infty}X(\omega)e^{j\omega t}d\omega $

$ x(t)=\frac{1}{2\pi}\int_{-\infty}^{\infty}cos(t)e^{j\omega t}d\omega $

$ x(t)=\frac{1}{2\pi}cos (t)\int_{-\infty}^{\infty}e^{j\omega t}d\omega $

$ x(t)=\frac{1}{2\pi}cos (t){\left.\frac{e^{j\omega t}}{j(t}\right]_{-\infty}^{\infty}} $

Alumni Liaison

Questions/answers with a recent ECE grad

Ryne Rayburn