Revision as of 12:07, 8 October 2008 by Jmazzei (Talk)

$ \ x(t) = e^{-2|t|}cos(8t) $

$ X(\omega) = \int_{-\infty}^{\infty} x(t) e^{-j\omega t} dt \! $

$ = \int_{-\infty}^{\infty} e^{-2|t|}cos(8t) e^{-j\omega t} dt \! $

$ = \int_{-\infty}^{0} e^{2|t|}cos(8t) e^{-j\omega t} dt \! + \int_{0}^{\infty} e^{-2|t|}cos(8t) e^{-j\omega t} dt \! $


after quite a bit of math I get the answer to be


$ \frac{1}{2}(\frac{1}{2 + j8 - jw} + \frac{1}{2 -j8 -jw} + \frac{1}{2 - j8 - jw} \frac{1}{2 + j8 + jw}) $


I'm not sure if I'm right though because when I checked it in matlab the answer I got was

 4*(68+w^2)/(68+w^2-16*w)/(68+w^2+16*w) <\pre>

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BSEE 2004, current Ph.D. student researching signal and image processing.

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