Fourier series coefficients for CT signal
CT Signal
- $ \, x(t)=6sin(6t) $
Fourier series coefficients
- $ x(t)=\sum_{k=-\infty}^\infty a_k e^{jk\omega_0 t} $
- $ \, x(t)=6sin(6t) = 6\cdot\frac{e^{j6t}-e^{-j6t}}{2j}=3(e^{j6t}-e^{-j6t}) $
- $ \, x(t)=3e^{j6t}-3e^{-j6t} $
- $ \, a_1 = 3\ ,\ a_{-1} = 3 $
