Revision as of 16:37, 26 September 2008 by Jwise (Talk)

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CT LTI signal:

$ y(t) = 3x(t-1)+x(t+3)-x(t)\! $

Part A

$ h(t) = 3\delta(t-1)+\delta(t+3)-\delta(t)\! $

$ H(j\omega) = \int_{-\infty}^{\infty}3\delta(t-1)+\delta(t+3)-\delta(t)\! $

Part B

Alumni Liaison

Correspondence Chess Grandmaster and Purdue Alumni

Prof. Dan Fleetwood