Question
A signal x(t)
1) x(t) is real
2) x(t) is odd
3) peak to peak value of 6
4) x(t) is periodic with period T = 4
5) a0 = 0
Answer
$ x(t)=\frac{3}{2}sin(\frac{2\pi}{5}t) $ </font>
A signal x(t)
1) x(t) is real
2) x(t) is odd
3) peak to peak value of 6
4) x(t) is periodic with period T = 4
5) a0 = 0
$ x(t)=\frac{3}{2}sin(\frac{2\pi}{5}t) $ </font>