Revision as of 14:57, 26 September 2008 by Kadafin (Talk)

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$ \ x(t) = \cos(4t\pi /6) + \sin(3t \pi /6) $


$ x(t)=({ e^{j 4t\pi/6} + e^{-j4t\pi/6} \over 2}) + ({ e^{j3t\pi/6} - e^{-j3t\pi/6} \over 2j }) $


$ a_k=\frac{1}{T}\int_0^Tx(t)e^{-jk\omega_0t}dt $


$ T = 2\pi $

$ x(t)=({ e^{2\pi jt/3} + e^{-2\pi jt/3} \over 2}) + ({ e^{2\pi j3t/12} - e^{-2\pi j3t/12} \over 2j }) $

Alumni Liaison

Correspondence Chess Grandmaster and Purdue Alumni

Prof. Dan Fleetwood