Define a CT Signal and its Fourier Series Coefficients
Periodic CT Signal: x(t) = 5cos(6t) + 2sin(3t)
= $ 5 * \frac {e^{j6t} + e^{-j6t}}{2} + 2 * \frac {e^{j3t} - e^{-j3t}}{2j} $
= $ \frac{5}{2} * e^{j6t} - \frac{5}{2} * e^{-j6t} + j * e^{j3t} -j* e^{-j3t} $
$ a1 = \frac {t}{2} $
$ a-1 = \frac{5}{2} $
