Revision as of 11:25, 25 September 2008 by Huang122 (Talk)

LTI System: $ y(t) = Kx(t)\, $ where K is a constant

Unit Impulse Response: $ h(t) = K \delta(t)\, $

Frequency Response:

$ x(t) = \sum^{\infty}_{k = -\infty} a_k e^{jk\pi t}\, $

then y(t)=\sum^{\infty}_{k = -\infty}a_k*(h(t)*e^{jj\omega_0 t})

$ H(s) = \int^{\infty}_{-\infty} h(\tao)e^{-j\omega_0 r} d\tao $ by definition

Alumni Liaison

Sees the importance of signal filtering in medical imaging

Dhruv Lamba, BSEE2010