CT LTI system:
y(t) = 10x(t-1)
plugging in delta(t) into the system we get:
h(t) = 10delta(t-1)
$ H(s) = \int_{-\infty}^{\infty} h(t)e^{-st} $
$ H(s) = \int_{-\infty}^{\infty} 10delta(t-1)e^{-st} $
$ H(s) = 10\times\int_{-\infty}^{\infty} 10delta(t-1)e^{-st} $
