Guess the Signal
1. $ x[n] $ is periodic with N=8.
2. $ \sum_{n=2}^{9}(-1)^{\frac{3}{4}n}x[n]=4 $.
3. $ a_3=a_5 $.
4. $ \sum_{k=0}^{7}a_k=1 $.
So What Is x[n]?
Given the first property of the signal, we can rewrite the bounds of summation in the second property since the zeroth term is the same as the eighth term and the first term is the same as the ninth term. Furthermore, we know that
