Revision as of 16:29, 19 September 2008 by Huang122 (Talk)

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Your example is quite interesting.
With a constant output, it's hard to distinguish which input it is responding to. You can say it's y(t)=x(t) or y(t)=x(t-1) or y(t)=x(t+1).
Yet for such a system, no previous or future states are needed to remember as they yield the same output. So take it as a whole I agree that it would be memoryless.

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Xujun Huang


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