Revision as of 07:09, 19 September 2008 by Longja (Talk)

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The overall response for this system is

$ f(t) = tf(-t) $

To relate to the systems that were already use in example

$ \cos(2t) = \frac{e^{i2t}+e^{-i2t}}{2} $

So when the signal is run through the system the following is what is produced

$ \frac{e^{i2t}+e^{-i2t}}{2}=\frac{te^{-i2t}+te^{i2t}}{2} = t\frac{e^{-i2t}+e^{i2t}}{2} = t\cos(2t) $

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Ryne Rayburn