Revision as of 05:15, 12 September 2008 by Sparksj (Talk)

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If

$ x(t) \to System \to y(t) $

implies,

$ x(t-t_0) \to System \to y(t-t_0) $

for any $ x(t) $, then the system is time invariant.


Example of a time-invariant system:

$ System = \sqrt{t} $

$ x(t) = t + 2 $, $ t_0 = 1 $

$ x(t) \Longrightarrow System \Longrightarrow \sqrt{t + 2} $

$ x(t-t_0) \Longrightarrow System \Longrightarrow \sqrt{t + 1} = \sqrt{t +2 -t_0} \therefore $ the system is time-invariant.


Example of a time-variant system:

$ System = t^2 $

$ x(t) = t + 2 $, $ t_0 = 1 $

$ x(t) \Longrightarrow System \Longrightarrow (t + 2)^2 = t^2 + 4t + 4 $

$ x(t-t_0) \Longrightarrow System \Longrightarrow (t + 1)^2 = t^2 + 2t + 1 \neq t^2 + 4t +4 - t_0 \therefore $ the system is not time-invariant.

Alumni Liaison

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Ryne Rayburn