Revision as of 18:30, 11 September 2008 by Han45 (Talk)

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part a

it can't be a time invariant because output is not same.

$ X_k[n] = \delta[n-k] $

$ \delta[n-k]\rightarrow time delay\rightarrow\delta[n-k-n_0]\rightarrow system \rightarrow (k+n_0+1)^2\delta[n-(k+n_0+1)] $

$ \delta[n-k]\rightarrow system \rightarrow Y_k[n] \rightarrow $

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